chapter 13 problem 5 ignment MESSAGE MY INSTRUCTOR FULL SCREEN PRINTER VERSION B
ID: 1793855 • Letter: C
Question
chapter 13 problem 5
Explanation / Answer
Solution:
As the slabs are having equal area and thickness So Using ,
k1 x Delta T1 = k2 x Delta T2
=> 110 x 20 = k2 x 10
=> k2 = 220 J/(s·m·C°).
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