The answer for 2 is C, and the answer for 3 is D. Can anyone explain them in det

Question

The answer for 2 is C, and the answer for 3 is D. Can anyone explain them in detail? Thank you.

2. Enzymes are large molecules that play the role of catalysts in biological reactions at 37 °C in our bodies. When most biological enzymes are heated to about 70 oC, the catalytically active form looses its catalytic activity because of the transformation enzyme aq) enzyme (II)(aq) Which of the following statements is correct concerning the properties of enzymes in our bodies? A) The transformation enzyme(I)(aq) me (II)(aq) is an exothermic process B) The transformation enzyme(I)(aq) me (II)(aq) is a non-spontaneous process at 70 OC C) The active form (I) of the enzyme is more ordered (with a smaller number of microstates than the inactive form (II) of the enzyme (that has a larger number of microstates D) The transformation enzyme enzyme (II)(aq) is a non-spontaneous (I)(aq) process at every temperature. E) The transformation enzyme (I)(aq) enzyme (II)(aq) is a spontaneous process only at low temperatures. 3. Ethylene glycol, CH2 is widely used as an antifreezing agent. The following information is available for liquid ethylene glycol at 25 °C: AHO (CH2OHCH2OH, liq)--454.8 kJmol AGO (CH2OHCH2OH, liq) -323.1 kJ mol 1 Using the data above together with the followiing data at the same temperature: S (C,s,graphite 5.74 J K mol So(H2,g) 130.7 J i mol S CO2,g 205.1 JK 1 mo 1 calculate the standard molar entropy of ethylene glycol at 25 oC A) -441.7 JK mol 1 B) 608.7 JK mol 1 C) -100.2 JK mol D) 167.0 JK mol 1 E) 341.5 J K-1 mol

Explanation / Answer

Answer 2. Statement C

At 70°C, transformation of the enzyme would be spontaneous. So, statement 'B' would be incorrect. The number of microstates is directly proportional to the entropy. At higher temperature, entropy would be higher, so the number of microstates would also be higher; therefore, statement 'C' is true. Statements 'D' and 'E' are totally incorrect. Please note that enzyme is spontaneous at a particular temperature only. This temperature is known as 'optimum temperature'. Statement ‘A’ is also wrong, because this is an endothermic process; taking heat and converting into a more disordered form.

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