PHY-111 Topic 6 Homework Begin Date: 8/28/2017 12:00:00 AM- Due Date: 11/26/2017

Question

PHY-111 Topic 6 Homework Begin Date: 8/28/2017 12:00:00 AM- Due Date: 11/26/2017 11:59:00 PM End Date: 11/29/2017 11 39-00 PM (1%) Probleu 30: A 0.055-kg ice cube at-30.0°C is placed in 0.45 kg of 35.0°C water in a very well-insulated container. The latent heat of fusion for water is Lf 79.8 kcal/kg Solids Aluminum Concrete 900 0.215 840 0.20 840 387 840 2090 0 0.0924 Glass Ice (average) Liquids 0.50 Water 4186 1.000 Gases Steam (100C) 1520 (2020) 0,363(0.482) Otheexpertta.com D What is the final temperature of the water, in degrees Celsius? Grade Summary Deductions 0% Late work % Late Potential 75% 75% tanO sin cotansin acost atan() acotano I sinh()! * | 1 | 2 | 3 | 45 6 Submissions Attempts remaining S (3% attempt) detailed view ed cosh0 anh cotanh0 ed Degrees Radians ed Hint I give up! ed Hints: 0% deduction per hit. Hints rena ning- Feedback: 19i deduction per feedback ed ed ed ted ted Submission History Answer Hints Feedhack Totals Totals 09 : 04

Explanation / Answer

Heat gain by ice = heat lost by water. Let all ice melts and Tf is greater than zero.If final value of Tf is positive then our supposition is correct.

m1*S1*30 + m1*L + m1*S2*(Tf-0) = m2*S2*(35-Tf)

0.055*0.50*30 + 0.055*79.8 + 0.055*1*Tf = 0.45*1*(35-Tf)

Tf = 20.86 C answer

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