215.2 atr \", 34 =215.79 rad Problem 2: Consider a rigid steel beam of length L-

Question

215.2 atr ", 34 =215.79 rad Problem 2: Consider a rigid steel beam of length L-10.5 m and mass mp-388 kg resting on two supports, one at each end. A worker of mass mw 64 kg sits on the beam at a distance x from support A. Refer to the figure. Part (a) Enter an expression for the force support B must exert on the beam in order for it to remain at rest, in terms of defined quantities and Expression Select from the variables below to write your expression. Note that all variables may not be required. , y, , 0, d, g, h,j, L, m, mb, mw, n, P, x Part (b) When the worker sits at a distance x - 8.5 m from support A, calculate the force, in newtons, that support B must e in order for it to remain at rest. Use g with three significant figures. Numeric : A numeric value is expected and not an expression. 2270 N. At what distance x, in meters, from support A Part(e) The force exerted on the beam by support A is measured and found to be F A 45tx.theexpertta.com/Common/ViewAssignmentDetails.aspx

Explanation / Answer

a) As the beam is in equilibrium, net force and net torque acting on the beam must be zero.

Apply net torque about left end = 0

FB*L*sin(90) - mB*g*(L/2)*sin(90) - mW*g*x*sin(90) = 0

FB*L - mB*g*(L/2) - mW*g*x = 0

FB = mB*g/2 + mW*g*x/L <<<<<------------Answer

b) FB = 388*9.8/2 + 64*9.8*8.5/10.5

= 2409 N <<<<<------------Answer

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