Please answer all This print-out should have 15 questions. Multiple-choice quest

Question

Please answer all This print-out should have 15 questions. Multiple-choice questions may continue on the next column or page find all choices The magnetic field over a certain range is before answering. 1 of 3 005 (part 1 of 3) 10.0 points given by B = Bri + B), where Br = 3 T and B 7 T. An electron moves into the field with a velocity t-Uz ^+tw+Vz k, where Vz = 2 m/s, t', = 6 m/s and v: = 7 m/s. 001 (part 1 of 2) 10.0 points A uniform 1.5 T magnetic field points north. If an electron moves vertically downward (to- ward the ground) with a speed of 2.4 × 107 m/s through this field. The charge on the electron is-1.602 What is thei component of the force ex- Answer in units of N 10-19C. The charge on a proton is 1.60× 10-19 a) What is the magnitude of the force acting erted on the electron by the magnetic field? on it? Answer in units of N 006 (part 2 of 3) 10.0 points What is the j component of the force? 002 (part 2 of 2) 10.0 points Answer in units of N b) What is the direction of the force? 007 (part 3 of 3) 10.0 points What is the k component of the force? 1. South 2. None of these 3. North 4. East 5. West Answer in units of N 008 (part 1 of 3) 10.0 points A particle with charge and mass m is un- dergoing circular motion with speed v. At t = 0, the particle is moving along the nega- tive r axis in the plane perpendicular to the magnetic field B, which points in the positive direction (up from the plane of the figure). 003 10.0 points An electron in a vacuum is first accelerated by a voltage of 31200 V and then enters a region in which there is a uniform magnetic field of 0.255 T at right angles to the direction of the electron's motion. The mass of the electron is 9-11 × 10-31 kg What is the magnitude of the force on the Answer in units of N and its charge is 1.60218 × 10-19 C. Find the magnitude of the centripetal ac- celeration ( electron due to the magnetic field? a). gem 004 10.0 points A proton moves perpendicularly to a mag netic field that has a magnitude of 5.74 x 102 The charge on a proton is 1.60× 10-19 C. What is the speed of the particle if the 4,a= nitude of the magnetic force on it is 4.40 × 0 "N? Answer in units of m/s. g m

Explanation / Answer

Question 001) Given , B = 1.5 T , v = 2.4*10^7 m/s , q = 1.6*10^-19 C

So ,

a) F = q*v*B*sin(©)

Here angle(©) = 90° ,

F = 1.5*2.4*10^7*1.6*10^-19*sin(90°)

F = 5.76*10^-12 N

Part B) Direction of force is towards the west by using the right hand thumb rule

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