boih.pa 3/10 VA SP17 soln.pdf e. Centimeters A force in the positive direction o
ID: 1794426 • Letter: B
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boih.pa 3/10 VA SP17 soln.pdf e. Centimeters A force in the positive direction of an x axis is applied to a 0.5 kg ball initially moving at 12 m/s in the negative direction of the x axis. The force varies in magnitude, and the impulse has a magnitude of 20 Ns. What is the x component of the ball's momentum just after the force is applied? Indicate the direction by including a plus or minus sign. 2. a. -14 kg-m/s b. 14 kg-m/s c. -26 kg.m/s d. 26 kg m/s e. -6 kg m/s 3. In the figure below, block A (mass 2 kg) slides into block B (mass 1 kg) along a frictionless surface. The directions of the velocities before the collision are indicated; the corresponding speeds are vu- 4 m/s and v-2 m/s. The blocks stick together after the collision. What is the speed of the two block system after the collision? VAN a. 2 m/s b. 3 m/s 4/3 m/s d. 8/3 m/s 4. Consider the collision in the previous problem. Let Ki be the total kinctic energy of the two-block system before the collision and K be the total kinctie energy of the system after the collision. Which statement is true? Ask meExplanation / Answer
2) b) 14 kg.m/s
Apply, Impulse = change in momentum
Impulse = Pfx - Pix
Pfx = Pix + Impulse
= m*vix + Impulse
= 0.5*(-12) + 20
= 14 kg.m/s
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