In a physics laboratory experiment, a coil with 200 turns enclosing an area of 1

Question

In a physics laboratory experiment, a coil with 200 turns enclosing an area of 11.1 cm2 is rotated during the time interval 3.50×102 s from a position in which its plane is perpendicular to Earth's magnetic field to one in which its plane is parallel to the field. The magnitude of Earth's magnetic field at the lab location is 5.10×105 T .

Part A

What is the magnitude of the magnetic flux (initial) through the coil before it is rotated?

Express your answer numerically, in webers, to at least three significant figures.

Part B

What is the magnitude of the magnetic flux final through the coil after it is rotated?

Express your answer numerically, in webers, to at least three significant figures.

Part C

What is the magnitude of the average emf induced in the coil?

Express your answer numerically, in volts, to at least three significant figure

Explanation / Answer

Given

no of turns is N = 200  

Area A = 11.1 cm^2 = 11.1*10^-4 m^2

time duration is dT = 3.50*10^-2 s

magnetic field is B = 5.10*10^-5 T

Part A

magnitude of the magnetic flux (initial) through the coil before it is rotated

by definition of magnetic flux is phi = B*A*cos theta

where theta is the angle between the magnetic field and normal to the surface area  

here theta is zero

so

flux phi = B*A cos0 = B*A

phi1 = B*A = 5.10*10^-5*11.1*10^-4 Wb

Phi1 = 5.661*10^-8 Wb

Phi1 = 56.61*10^-9 Wb

Part B

when the coil is rotated so that the plane of the coil is perpendicular to the magnetic field, so that the angle theta is 90 degrees

so the magnetic flux phi2 = B*A cos 90 = 0 Wb

Part c

the induced emf is e = -dphi/dt

e = - (phi2-phi1)/dt

e = -(0-56.61*10^-9)/(3.50*10^-2) V

e = 1.6174286*10^-6 V

the average emf induced in the coil is e = 1.6174286*10^-6 V

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.