CH29 HN Problem 29 27 previous | 9 of 20 I next » Problem 29.27 Part A An electr

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CH29 HN Problem 29 27 previous | 9 of 20 I next » Problem 29.27 Part A An electron moves in the magnetic field B- 0.600i T with a speed of 1.40×107 m/s inte directions shown in the figure. For each, what is magnetic force F on the electron? (Eigure 1) Express vector F in the form of Fe. F F, where the x, y, and z components are separated by commas. ules F 0,0, 1.44 101 Submit My Answers Give Up Incorrect: Try Again; 2 attempts remaining Part B Fi. where the x, y, and z components are separated Express vector F in the form of Fe F by commas F 0, 1.15 10-13 1.15-10-1 N My Answers Give Up Incorrect: Try Again; 4 attempts remaining Provide Feedback Continue CMCEWENvd Type here to search

Explanation / Answer

F = q*v cross B

1)

-1.60*10^-19C *( 1.40*10^7(-j)) x 0.600T(i) = 1.344*10^-12 N in the -k direction so

F = 0 , 0 , -1.344*10^-12 N

2)

F= -1.60*10^-19*1.40*10^7*(0.707(-j) + 0.707(k)) x 0.600T(i)  

F = 0 , -5.91x10^-13 N , -5.91x10^-13 N

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