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Thank you eC Secure https://edugen.wileyplus.com/edugen/student/mainfr.uni ce Assignment Gradebook ORION Downloadable eTextbook ment FULL SCREEN | PRINTER VERSION BACK NE Chapter 12, Problem 036 GO An aluminum can is filled to the brim with a liquid. The can and the liquid are heated so their temperatures change by the same amount. The can's initial volume at 5 °C is 5.5 x 10-4 m3. The coefficient of volume expansion for aluminum is 69 × 10-6 (C")-1. When the can and the liquid are heated to 77 °C, 6.9 × 10-6 m3 of liquid spills over. What is the coefficient of volume expansion of the liquid? the tolerance is +/-2% LINK TO TEXT vascript:showNext):

Explanation / Answer

let the volume expansion of the liquid is b

NOw, for the spilled liquid

6.9 *10^-6 = change in volume of liquid - change in volume of glass

6.9 *10^-6 = 5.5 *10^-5 * (b - 3 * 69 *10^-6) * (77 - 5)

solving for b

b = 0.00195 1/degree C

the volume expansion of the liquid is 0.00195 1/degree C

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