(13%) Problem 5: A diatomic ideal gas goes through the cycle a b c d a as shown
ID: 1795189 • Letter: #
Question
(13%) Problem 5: A diatomic ideal gas goes through the cycle a b c d a as shown in the figure. Processes ab and cd are isothermal and occur at temperatures TH 420 K and Tc- 287 K, respectively. There are n 15 moles of this gas in the system, and the initial volume is Va = 0.088 m. 3% ©theexpel 25% Part (a) Calculate the work Wab, in joules, done by the gas during the process a b Grade S Potentia Submis (4% per 45 6 cotan asin0 atan acot sinhO cos 0 Degrees Radians Submit Hint I give up! Hints: 0% deduction per hint. Hints remaining: 3 Feedback: 2% deduction per feedback. 25% Part (b) Calculate the work Wbc done by the gas, in Joules, during the process b c. 25% Part (c) Calculate the total work W done in the entire cycle, in Joules 25% Part (d) Calculate the total heat Q, in Joules, flowing into the gas in a complete cycleExplanation / Answer
work done in isothermal process Wab = 2.3026*n*R*TH*log(Vb/Va)
vb = 3*va
Wab = 2.3026*15*8.314*420*log(3) = 57544 J
------------------------
part(b)
work done = slope
heare the slope = 0
Wbc = 0
============================
Wcd = 2.3026*R*Tc*log(vd/vc)
Wcd = 2.3026*15*8.314*287*log(1/3)
Wcd = -39321.53 J
Wda = 0
total work = Wab + Wbc + Wcd + Wda
total work = 57544 - 39321.53 = 18222.47 J
---------------------------
part(d)
total heat flowing = Q = 57544 J
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.