Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

a 220g ball os dropped from a height of 2.4 m, bounces on a hard floor,and rebou

ID: 1795578 • Letter: A

Question

a 220g ball os dropped from a height of 2.4 m, bounces on a hard floor,and rebounds to a height of 1.9 m ..1 Verizon 6:53 PM session.masteringphysics.com Problem 9.4 MasteringPhysics Problem 9.41 A 220 g ball is dropped from a height of 2.4 m, bounces on a hard floor, and rebounds to a height of 1.9 m max t (ms) 5 ms Q Tap image to zoom shows the impulse received from the floor Part A What maximum force does the floor exert on the ball? Express your answer to two significant figures and include the appropriate units. Fmax= 1 Value Units Submit Give Up

Explanation / Answer

Here , for the velocity of the ball

initial speed of ball before colliding , u = sqrt(2 * g *h)

u= sqrt(2 * 9.8 * 2.4)

u = 6.86 m/s

velocity after the collision

v =sqrt(2 * 9.8 * 1.9)

v = 6.102 m/s

Now, for the impulse

0.50 * Fmax * 5 * 10^-3 = 0.220 * (6.86 - (-6.102))

solving for Fmax

Fmax = 1140 N

the maximum force is 1140 N

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote