(796) Problem 6: Suppose a 23.5°C car tire contains 3.85 mol of gas in a 29.5 L

Question

(796) Problem 6: Suppose a 23.5°C car tire contains 3.85 mol of gas in a 29.5 L volume > 50% Part (a) What is the gauge pressure, in atmospheres, in the car tire? Grade Summa Deductions Potential 0% 100% sinO cotan0asin acos0 atan0 acotan sinhO cosh0 tanh cotanhO Submissions Attempts remaining: (10% per attempt) detailed view cos0 1 *1 23 END Degrees C) Radians DEL CLEAR Submit Hint I give up! Hints: 0% deduction per hint. Hint remaining 1 Feedback: 0% deduction per feedback. 50% Part (b) What will the gauge pressure be if you add a quantity of gas that had a volume of 2.00 L when it was at atmospheric pressure and the same temperature as the tire?

Explanation / Answer

a) PV = nRT

P (29.5) = 3.85 ( 0.082 ) ( 296.65 K)

P = 3.174 atm

b) number of moles

( 2L) ( 1tm) = n ( 0.082) (  296.65 K)

n = 0.1 moles

new pressure

P ( 29.5) = 3.95 ( 0.082) (  296.65 K)

P = 3.257 atm

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.