Problem 2 The 150 lb car of an amusement park ride is connected to a rotating te

Question

Problem 2 The 150 lb car of an amusement park ride is connected to a rotating telescopic boom. Part A When r = 16 ft , the car is moving on a horizontal circular path with a speed of 32 ft/s . If the boom is shortened at a rate of 3 ft/s , determine the speed of the car when r = 13 ft . Neglect the size of the car and the mass of the boom.(Figure 1) Express your answer with the appropriate units. v2 = SubmitMy AnswersGive Up Part B Also, find the work done by the axial force F along the boom. Express your answer with the appropriate units.

Problem 2 Part A The 150 lb car of an amusement park ride is connected to a rotating telescopic boom When T 16 ft, the car is moving on a horizontal circular path with a speed of 32 ft/s. If the boom is shortened at a rate of 3 ft/s, determine the speed of the car when r 13 ft. Neglect the size of the car and the mass of the boom.(Figure 1) Express your answer with the appropriate units 2ValueUnits Submit My Answers Give Up Figure 1 of 1 Part B Also, find the work done by the axial force F along the boom Express your answer with the appropriate units UFValue Units Submit My Answers Give Up de Feedbac Continue

Explanation / Answer

Part A )

given

r1 = 16 ft

r2 = 13 ft

v1 = 32 ft/s

v2 = ?

using angular momentum conservation

r1 m v1 = r2 m v2

v2 = r1 m v1 / r2 m

v2 = r1 v1 / r2

= 16 X 32 / 13

v2 = 39.38 ft/s

V2 = ( V2 + v22 )1/2

V2 = ( 32 + 39.382 )1/2

V2 = 39.49 ft/sec

Part B )

using equation

1/2 mv12 + Uf = 1/2 mV22

0.5 X ( 150 / 32.2 ) X 322 + Uf = 0.5 X ( 150 / 32.2 ) X 39.492   

Uf = 0.5 X ( 150 / 32.2 ) X 39.492 - 0.5 X ( 150 / 32.2 ) X 322

Uf = 0.5 X 4.658 X 39.492 - 0.5 X 4.658 X 322

Uf = 1247.086 ft.lb

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