The following motion represent a cart freely moves up and back down the plane. A
ID: 1796108 • Letter: T
Question
The following motion represent a cart freely moves up and back down the plane. Answer the questions 8-12 base on the displacement vs time graph recorded for the motion. 1o5 OD 2- 8) At what time the maximum postive velocity was recorded? t what time the maximum positive velocity was recorded? A) 2S B) 4S C) 6S D) Between 2-4S E) Between 4-65 9) At what time the maximum negative velocity was recorded? A) 2S B) 4S C) 6S D) Between 2-4S E) Between 4-6S 10) At what time the velocity was zero? A) 2S B) 4S C) 6S D) Between 2-4S 11) The motion has a positive acceleration at? E) Between 4-6S B) No positive Acceleration C) only between 2-4s A) 4S D) Only between 4-6S E) Between 2-6S 12) The motion has a negative acceleration at? B) No negative Acceleration C) only between 2-45 A) 4S D) Only between 4-6S E) Between 2-6SExplanation / Answer
8) Velocity is obtained by slope of displacement vs time graph
the maximum positive velocity is given by maximum positive slope of displacement vs time graph
That time is at 6seconds. Correct option is (c)
9)
the maximum negative velocity is given by maximum negative slope of displacement vs time graph
That time is at 2 seconds. Correct option is (a)
10)the velocity is zero when the slope of displacement and time graph is zero. That time is 4 seconds
11)we will see positive acceleration when velocity increases with time.That is happening throughtout the motion.Therefore correct answer is (E)
12)There is no negative acceleration of the cart. Correct option is (B)
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