A population of wild poppies endemic to the California Channel Islands occurs in

Question

A population of wild poppies endemic to the California Channel Islands occurs in two discreet varieties: an crest from and low ground hugging form. The morphology of growth is governed by a single somatic gene: erect is dominant and ground-hugging is recessive. In 2005, population geneticist studied these poppies on remote and windy Sam Miguel Island and found the low growing form to be the most common variety - 925 of the 1602 plants identified and studied. In 2010 European honey boss were found on the island for the first time. Five years later another steady was conducted involving the poppies on San Miguel Island. By then the poppies has increase their range and their number on the island to 2980. Of these, 1907 exhibited the erect morphology.[For credit with these questions, show your work.] A. What was the allele frequency for the dominant allele in the 2005 poppy steady? B. Assuming the population was in Hardy-Weinberg equilibrium, how many individuals in the 2005 population would have been heterozygotes? C. What was the dominant allele frequency in the 2015 poppy population? D. Another group of scientist studied the introduced bees. They discovered the bees had become major vectors for the pollination of plants on the islands. Moreover, they found the bees were much more likely to visit the flowers of upright and erect plants than those of low-lying ground hugging plants. Applying this observation to the island poppies, which two assumptions for a Hardy-Weinberg population were being violated? Simple X-linked red-green color blindness affects 10% of the males but only 0.49% of the females in the U.S. population of 330 million. Assuming an even sex ratio for males to females, how many copies of the recessive allele responsible for color blindness are present in the U.S.? [Show your work.]

Explanation / Answer

Answer:

64).

One recessive allele is enough to produce color blind in the male, so 10% alleles of 330million population is responsible in males.

10% alleles out of 330 millions= (10/100 )330000000 = 33000000 alleles

Two recessive allele are needed to produce color blind in the male, so 0.49% means 0.98% alleles are needed for color blindness in females.

0.98% alleles out 330 millions =(98/100) 330000000 = 3234000 alleles

Total 36234000 recessive allele are responsible for colorblindness.

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