A moving charged particle (+q) produces a magnetic field B B = ( ? 0 / 4 ? ) [ (

Question

A moving charged particle (+q) produces a magnetic field B B=(?0/4?)[(qvcrossr)/r2]equation1

a)According to equation (1), what is the magnitude of the magnetic field |B| shown below,as a function of q, v, R and x?

the figure for both parts is the same

b)Demonstrate that results from part a) can be derived from the Ampere%u2019s law, asexpressed in eqn (2).

?EnclosedB?dl=?0(ic+?0(d?E/dt))equation2

(Hint: for part b), you need the following integration table and relation

?[rdr/(x2+r2)3/2=?1/x2+r2???????

the

the thethe fthe finig

Explanation / Answer

please post the table..

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