ampere, or ohm ( Ohm ). Although we show the CCVS symbol with four terminals, te

Question

ampere, or ohm ( Ohm ). Although we show the CCVS symbol with four terminals, terminals a and b and the lines joining them are not usually shown explicitly. The control current iab is typically the current through some other network component, as shown in Fig. 2.16 Determine voltage v2 for the network shown in Fig. 2.16. We can use KCL to establish that i 1 = 15 A and KVL gives us v2 = 6i1 = 6(15) = 90 V 64 degree + V2 (90) = 0 90 64 degree = V2 (15) 40/15 =15v2/15 6 = V2 6V = V2 64 degree - V2(i2) = 0 90 - V2 i2 = 0 V2(15)/15 = 60/15 V2 = 6

Explanation / Answer

i dont understand why r u doing dividing 15 from each equation using the of conversion at node incoming current =outgoing current so u can easily find that at node i=10+5 and it is given that voltage b/w two point (point out side 6i) =6i so u can find the voltage=6*15; and we know that at parallel condition voltage will be same so v2=90 or v2-6i=0 v2=6i=90

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