a)The switch is closed in the circuit below and the output waveform s(t) is obse

Question

a)The switch is closed in the circuit below and the output waveform s(t) is observed across thecapacitor. Using only the graph, determine the value of the capacitor C assuming it was initiallyuncharged. Do this by plotting ten values of the function ln(1-s(t)) spaced every 0.1 s and fittinga straight line to the data points using a ruler. Explain how to determine the value of C from theslope of this line and then using this explanation, determine its value. What is the timeconstant?

b) Design an experiment to measure the capacitance C replacing the DC voltage source and the switch in the circuit above with a function generator. Sketch the setup and discuss what measurements are required to determine the capacitance and specifically how to set up the frequency and waveform of the function generator if the capacitance is not known. What should the input look like in comparison to the output?

Any work or explanation shown will be grateful!

Explanation / Answer

Please ask if you have any doubt.I will help you.

Calculate the time at which capacitor will reach 0.63 times its maximum value. This time is time constant . from graph it is approximately 0.25 micro seconds. Project a line at 63% and find the time correclty if you need more accurate answer. :) :)

Time constant = RC = 0.25 micro seconds gives

C = 0.025 nF.

I do not have a camera for the second part .... Do rate my answer if you found it helpful fro the first part.

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