For the four load conditions RL = infinity (no load), RL = 10 k ohm, RL = 2.2 k

ID: 1810713 • Letter: F

Question

For the four load conditions RL = infinity (no load), RL = 10 k ohm, RL = 2.2 k ohm, and RL = 1 k ohm, determine the voltage gains Avi=v0/vi and Avs=v0/vs of the Common-Emitter (CE) amplifier of FIGURE 2. Also, for the same four load conditions, determine the input and output resistances Rj and R0. For the calculations, assume that the capacitors are short over the frequency range of interest, the Early effect is negligible (i.e., r0 = infinity), and the source resistance is Rs = 600 ohm. Report the results in Table P2. + 15V FIGURE 2: CE

Explanation / Answer

Av = (4.7||Rl)(0.255)

Rin = Rs+(22.22||3.9*100) = 22.82kohm (in all cases)

Rout= (4.7||Rl)

when Rl =infinity

Av = 1.199

Rout = 4.7k

Rl=10k

Av = 0.81

Rout = 3.19K

Rl =2.2 k

Av = 0.38

Rout= 1.5k

Rl= 1k

Av= 0.21

Rout = 0.824k

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For the four load conditions RL = infinity (no load), RL = 10 k ohm, RL = 2.2 k

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