(1) A current source of value 2cos(2t) A is used to power a string of 2W lightbu
ID: 1811049 • Letter: #
Question
(1) A current source of value 2cos(2t) A is used to power a string of 2W lightbulbs. If you wanted to replace this current source with a DC one, but have the same power drop, what DC current should you apply (one decimal place needed)? I=---- amperes
(2)A voltage source of value V=120cos(4t+pi) is applied to a resistor of value 10ohms. What is the average power dissipated in the resistor (integer number needed) Pav=----Watts
(3)A square wave voltage source with a peak value of 120V has a current of value 1A rms. What is the maximum average power this source can output? Pmax =-----Watts
(4)A voltage source of value V=6*sqrt(2)*cos(4t+45) is applied to a network of inductors, resistors and capacitors. You measure the current to be 1*cos(4t). What is the average power dissipated in the network (integer number needed)? Pave=-----Watts
Explanation / Answer
1) DC power value = rms power value in AC if we take the load as 1ohm so Required DC current = 2/root 2 = 1.414
2) Average power = Vrms2/R = (120/1.414)^2/10 = 720W
3) Maximum average power = 120*1 = 120W
4)pave = V*I = 6*1.414 AT AN ANGLE OF 45 DEGREES * 1 = 6w
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