Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

(1) A current source of value 2cos(2t) A is used to power a string of 2W lightbu

ID: 1811049 • Letter: #

Question

(1) A current source of value 2cos(2t) A is used to power a string of 2W lightbulbs. If you wanted to replace this current source with a DC one, but have the same power drop, what DC current should you apply (one decimal place needed)? I=---- amperes


(2)A voltage source of value V=120cos(4t+pi) is applied to a resistor of value 10ohms. What is the average power dissipated in the resistor (integer number needed) Pav=----Watts


(3)A square wave voltage source with a peak value of 120V has a current of value 1A rms. What is the maximum average power this source can output? Pmax =-----Watts


(4)A voltage source of value V=6*sqrt(2)*cos(4t+45) is applied to a network of inductors, resistors and capacitors. You measure the current to be 1*cos(4t). What is the average power dissipated in the network (integer number needed)? Pave=-----Watts

Explanation / Answer

1) DC power value = rms power value in AC if we take the load as 1ohm so Required DC current = 2/root 2 = 1.414

2) Average power = Vrms2/R = (120/1.414)^2/10 = 720W

3) Maximum average power = 120*1 = 120W

4)pave = V*I = 6*1.414 AT AN ANGLE OF 45 DEGREES * 1 = 6w