Phasors & Impedance Diagrams 1. A series RLC circuit connected to a 100-V 60-Hz

Question

Phasors & Impedance Diagrams 1. A series RLC circuit connected to a 100-V 60-Hz source draws a current of 2.5 A. The measured power factor for the circuit is 0.7 leading, and the inductive reactive power is 300VAr. Calculate the resistance, inductance and capacitance of the circuit and show the corresponding impedance diagram(5). 2. Find the equivalent impedance for Z1 = 60? L+60? and Z2 = 80? L-45? when these are connected in parallel? What are the branch currents and the total circuit current if the supply voltage to the circuit is VS = 240V L0?. Draw the current phasor diagram (5). Power Diagrams and Power Factor 3. Find the real power, reactive power, KVA and power factor of a load whose impedance is 60? L+60? when connected to a 120-V 60-Hz source. Draw the resulting power diagram (5). 4. The power factor of a load connected to a 120-V 60-Hz source is raised from 0.866 lagging to 0.966 leading by connecting a 110.5-?F capacitor in parallel with the load. Determine the load current I1 and the circuit current IT. E x p l a i n why the power factor correction capacitor is connected in parallel and not in series with the load? https://dyp.im/delete/rDul9UWrLfsKhMaR

Explanation / Answer

Firstly, I(L)X(L) = I(L)^2X(L) = 2.5^2 * X(L)

300/6.25 = 48 So, X(L) = 48 ohm So, X(L) = omega*L

So, 48 = 2*3.14*60 * L

L = 0.1274 H

Z = V/I = 100/2.5 = 40 ohm

power factor = R/Z

0.7 = R/40 = 28 ohm , R = 28 ohm

Now,

Z^2 = R^2 + (XC - XL)^2

XC - XL = sqrt(Z^2 - R^2) = 816

XC = 864

C = 1/(864*2*3.14*60) = 3 micro farad

Zeq = 34.28angle(38.53)

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.