How do you get +1 in equation 3, I didn\'t get it at all! Given that F = 100 N C

Question

How do you get +1 in equation 3, I didn't get it at all! Given that F = 100 N Clockwise moment created is M = 20 N · m The moment of the force F about point O is expressed as M = M0 Accordingly, we have M0 = -100 N times sin theta times (0.3m times cos 60theta) + 100 N times cos theta times (0.3m times sin 60 theta + 0.05m) M0 = (-15sin theta) N · m + (30.98 cos theta)N · m From (1) and (2), we have 20 N · m = (-15sin theta) N · m + (30.98 cos theta) N · m 0.75 sin theta - 1.549 cos theta + 1 = 0 We solve (3) by trial and error method. With theta = 28degree,we obtain from (3) -0.01555 0 With theta = 29degree, we obtain from(3) 0.0088 0 With theta = 28.6 degree, we obtain from (3) 0.0009 0 By solving (3), in a trial and error basis, we obtain theta = 28.6 degree The angle is theta = 28.6 degree

Explanation / Answer

All they did was move all the terms to the left side...thendivided both sides by 20... 20 N m + 15sin - 30.98cos = 0 Divide by 20...you get: 1 N m + .75sin - 1.549cos = 0 Hope this helps... PLEASE RATE!!!!!!!!!!

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