I have a homework problem that is puzzling me a little theproblem states a manom

Question

I have a homework problem that is puzzling me a little theproblem states a manometer is connected to an air duct to measurethe pressure inside. Given the difference in the manometer levelsis h = 17mm determine the following. a. the absolute pressure in the duct. b. The value of h in meters if water is used in the manometerinstead of mercury. given Patm = 102 kPa: mercury = 13,700kg/m3: water = 995 kg/m3; and g = 9.81m/s2. for part a i came up with Patm = gh =102kPa+(13700kg/m3)(9.81m/s2)(0.017m)(1kpa/1000N/M2) giving me 104.28kPa part b i used h= Patm/g= 102/(995x9.81)x(1000/1) whichgave me 10m i dont know if i am correct on part b could use someadvice I have a homework problem that is puzzling me a little theproblem states a manometer is connected to an air duct to measurethe pressure inside. Given the difference in the manometer levelsis h = 17mm determine the following. a. the absolute pressure in the duct. b. The value of h in meters if water is used in the manometerinstead of mercury. given Patm = 102 kPa: mercury = 13,700kg/m3: water = 995 kg/m3; and g = 9.81m/s2. for part a i came up with Patm = gh =102kPa+(13700kg/m3)(9.81m/s2)(0.017m)(1kpa/1000N/M2) giving me 104.28kPa part b i used h= Patm/g= 102/(995x9.81)x(1000/1) whichgave me 10m i dont know if i am correct on part b could use someadvice giving me 104.28kPa part b i used h= Patm/g= 102/(995x9.81)x(1000/1) whichgave me 10m i dont know if i am correct on part b could use someadvice

Explanation / Answer

for a check wheter you are using the vaccuum formula or the normalatm (ambient) form but it looks like u calculated the gage pressurenot the atm pressure... the atm presssure should be 101.1(or101325) Pa the gage pressure is gh which adds up to be theabsolute pressure, but it seems you have that.... i would check thegh cause the units on that is a Newton not N/m2hope that gets you on the right track...

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