As slider blok A moves downward at a speed of 0.5 m/s, thevelocity with respect
ID: 1816005 • Letter: A
Question
As slider blok A moves downward at a speed of 0.5 m/s, thevelocity with respect to A of the portion of belt B between idlerpulleys C and D is vCD/A = 2 m/s (angle: SW at degrees). Determine the velocity of portion CD of the beltwhen (a) = 45o, (b) = 60o.(The diagram shows slider block A moving SW at 65o andportion CD of the belt moving SW-NE at degrees). The issues I had with this problem are: 1) howdo I know which direction CD is moving...SW or NE? ad 2)fromthe diagram, it looks like portion CD of the belt is SW-NE at degrees, and, the problem stated that vCD/A isalso SW at degrees. How can both sides of aparallelogram be at the same angle? As slider blok A moves downward at a speed of 0.5 m/s, thevelocity with respect to A of the portion of belt B between idlerpulleys C and D is vCD/A = 2 m/s (angle: SW at degrees). Determine the velocity of portion CD of the beltwhen (a) = 45o, (b) = 60o.(The diagram shows slider block A moving SW at 65o andportion CD of the belt moving SW-NE at degrees). The issues I had with this problem are: 1) howdo I know which direction CD is moving...SW or NE? ad 2)fromthe diagram, it looks like portion CD of the belt is SW-NE at degrees, and, the problem stated that vCD/A isalso SW at degrees. How can both sides of aparallelogram be at the same angle?Explanation / Answer
It would be easy to solve if you post up the picture diagram ofproblem from the book here. Most of us do not have thetextbook.
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