A researcher has isolated a new enzyme called the Holiday Bowl enzyme. Can you p

Question

A researcher has isolated a new enzyme called the Holiday Bowl enzyme. Can you please go through the problem and show the work up of how to get the answers.

6. (6 points) A researcher has isolated a new enzyme called the Holiday Bowl enzyme. 1 when (a) (2 points) The Holiday Bowl enzyme (HBase) exhibits a of 24 uM [El-2 nM Calculate the kcat for HBase (include the correct unit kcat 1200 s (b) (2 points) when CEt] 2 nM. and [s] 400 nM.HBase exhibits a Vo of 04 uMM s Calculate the Km for HBase Cinclude the correct units) 2 uM (c) (2 points) USC is a very weak uncompetitive inhibitor of HBase. The Lineweaver-Burke plot below has a line representing the activity of HBase in the absence of the inhibitor USC. In the plot. draw a line that might be obtained in the presence of some amount of inhibitor Usc. +USC

Explanation / Answer

Ans a. Kcat = Vmax / [Et]

[Et] = 2 nM = 2 × 10-9 M

Vmax = 2.4 µMs-1 = 2.4 × 10-6 Ms-1

= 2.4 × 10-6 / 2 × 10-9

= 1.2 × 103 s-1

Therefore Kcat = 1200 s-1

Ans b. V0 = Vm [S]/Km + [S]

  Km + [S] = Vm [S]/V0

   Km + 0.4 = 2.4 [0.4] / 0.4

  Km + 0.4 = 6[0.4]

Km + 0.4 = 2.4

Km = 2.4-0.4

Therefore Km = 2 µM

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