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<p>Below 1155 K, the &#949; form of titanium is stable; above 1155 K, the &#946;

ID: 1819072 • Letter: #

Question

<p>Below 1155 K, the &#949; form of titanium is stable; above 1155 K, the &#946; form is the stable phase,<br />whereas the &#949; form becomes metastable. e entropy di&#154;erence between the phases is<br />given by &#8710;S&#949;&#8594;&#946; = 3.43 J/(mol K).e melting temperature of the &#946; phase is T&#946;m = 1940 K,<br />with &#8710;Sm = 9.02 J/(mol K).<br />If a piece of titanium would remain in the &#949; phase above 1155 K, at what temperature<br />would it melt?<br />Note: You may assume the entropies of transformation to be independent of temperature.</p>

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