i have three questions: 1) a composite section is formed using a W12x50 and segm
ID: 1824963 • Letter: I
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i have three questions: 1) a composite section is formed using a W12x50 and segment of 4-in. concert slab. the section resists a positive z bending of 95 ft-kips the reatio (es/ec) of the steal to the concreate is 8. a) find transformed section moment of inertia B) max stress on concret. c) max stress on steel. the other two questions are in the attachments with their graph
A polyethelyne liner of a settling pond in subjected to the stresses shown below. : a. Draw Mohr?s Circle for the plane stress condition. b. Determine the normal and shear stresses along the seam. c. Determine the maximum in and out of plane shear stresses for the liner. 2. A composite section is formed using a W12 x 5 and a segment of a 4-in. concrete slab. The section resists a positive Z bending moment of 95 ft-kips. The modular ratio (Es/Ec) of the steel to the concrete is 8. a. Find the transformed section moment of inertia for the section. b. Determine the maximum stresses in the concrete. c. Determine the maximum stresses in the steel. 3. Two boards are nailed together to form a T section, as shown below. A shear force V of 1500-N in the Y direction: a. What is the horizontal shear force q acting along the connection? b. If the nail capacity in shear is 760-N what is the required spacing? c. What is the maximum shear stress in the wood? Given: neutral axis is 170.9-mm from the bottom & Iz = 1.549 x 10^8-mm^4 i have three questions: 1) a composite section is formed using a W12x50 and segment of 4-in. concert slab. the section resists a positive z bending of 95 ft-kips the reatio (es/ec) of the steal to the concreate is 8. a) find transformed section moment of inertia B) max stress on concret. c) max stress on steel. the other two questions are in the attachments with their graphExplanation / Answer
solution: we have the equation t = F / A , from here find F F = t * A = 6 000 * ( pi * 0.3^2 /4) = 423.9 lb F(total)= 6 * F = 6 * 70.65 = 2543.4 lb. now we can find torque torque(total)= Force * Radius of action put the above found value of force we get = 2543.4* 2.5 in = 6358.52 lb.in --------- Ans
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