THe 50 kg crate is stationary when the force P is applied. Determine the resulti
ID: 1826696 • Letter: T
Question
THe 50 kg crate is stationary when the force P is applied. Determine the resulting acceleration of the crate if (a) P=0, (b) P=150 N, and (c) P=300 N
THe correct answrs are (a) 1.12 m/s^2 down, (b) 0, and (c) 2.04 m/s^2 up
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Explanation / Answer
a) Wsin(15)=50*9.81*sin(15)--------------------------------- force due to static friction f1=0.2*50*9.81*cos(15)------------------- Wsin(15)-f1=50*9.81*sin(15)-0.2*50*9.81*cos(15)>0----------------- so acceleration of crate=(50*9.81*sin(15)-0.15*50*9.81*cos(15))/50=55.8827488/50=1.117m/s^2 downward direction along the incline --------- b)when P=150N crate have zero acceleration as net force on crate don't overcome max static friction force ,so no movement and so no acceleration ------------------- c)acceleration =- (50*9.81*sin(15*0.0174532925)+0.15*50*9.81*cos(15*0.0174532925)-300)/50=2.0396m/s^2-------------- upward direction along the incline
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