A cable is attached between B and C . The cable is attached in such a way that i
ID: 1828450 • Letter: A
Question
A cable is attached between B and C. The cable is attached in such a way that it has a tension of TBC along its length. The tensile force will attempt to pull B toward C. The force exerted on B has a z component with a magnitude of
To find a position vector between two arbitrary points. As shown, two cables connect three points. C is 2 ft below A and connected to A by a cable 5.690 ft long. Cable AC forms an angle ?=60? with the positive y axis. B is 10 ft above C and the distances Bx and By are 6.5 ft and 3.5 ft, respectively. A cable is attached between B and C. The cable is attached in such a way that it has a tension of TBC along its length. The tensile force will attempt to pull B toward C. The force exerted on B has a z component with a magnitude of 10 lb . What is the magnitude of the tension in the cable, TBC? I have found the position vectors from A to B, A to C, and B to C. AB = (-6.5,3.5,8.0) AC = (4.50,2.85,-2.00) BC = (11.0,-.650,-10.0)Explanation / Answer
Assuming your BC position vector is correct, the solution is as follows:
unit vector along BC => (0.74, -0.0437, -0.67) (just divide BC vector by its magnitude)
Tension T is along this direction.
z-component of T is : T*0.67 = 10
implies , tension, T equals 15 lbs
hope it helps!
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