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ID: 1828554 • Letter: #

Question

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The three stress states shown below are applied to a material that yields when the max shear stress equals 25 ksi (i.e. the Tresca yield criterion is ?critical = 25 ksi) . For each stress state below, calculate the value of ? at which the material will yield and the rotation of the element, with respect to the orientation shown below, that results in the maximum shear.

The three stress states shown below are applied to a material that yields when the max shear stress equals 25 ksi (i.e. the Tresca yield criterion is ?critical = 25 ksi) . For each stress state below, calculate the value of ? at which the material will yield and the rotation of the element, with respect to the orientation shown below, that results in the maximum shear.

Explanation / Answer

let maximum extension/length be =a/l;(for 25 ksi) nu=poisson ration

so, a/l*E=25; Now coming to the question


part1) sigma/E=a/L;sigma=E*a/L=25ksi;


part 2) a/L=1/E(sigmax-nu*sigmay) [sigmay=-sigmax acting in opp. direction]

E*a/l = (1+nu)*sigma; so, sigma=25/(1+nu);



part 3) a/L=1/E(sigmax-nu*sigmay) [sigmay=sigmax acting in same direction]

E*a/l = (1+nu)*sigma; so, sigma=25/(1-nu);

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