Water flows from section1 to section 2 in the pipe shown in the figure. For the
ID: 1828935 • Letter: W
Question
Water flows from section1 to section 2 in the pipe shown in the figure. For the data given in the figure determine the velocity of flow and the fluid pressure at section 2. Assume that the total head loss from section 1 to section 2 is 3 m. find v2=? and p2=?
I know the answer is 8 m/s and 260kpa. But how do I find this?
Explanation / Answer
from mass continuity equation; A1*v1 = A2*v2 => (pi*100^2/4)*2 = (pi*50^2/4)*v2 => v2 = 8 m/s applying bernoulli's equation between points 1 & 2; [P1/(p*g)] + [v1^2/2g] + z1 = [P2/(p*g)] + [v2^2/2g] + z2 + head loss => [300*10^3/(1000*9.8)] + [2^2/(2*9.8)] + 2 = [P2/(1000*9.8)] +[8^2/(2*9.8)] + 0 + 3 => 30.612 + 0.204 +2 = [P2/(9800)] + 3.265 + 3 => P2 = 260199.8 Pa => P2 = 260 kPa (approx.)
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