So far I was able to calculate the mean and standard deviation, where Mean = 23
ID: 1829175 • Letter: S
Question
So far I was able to calculate the mean and standard deviation, where Mean = 23 and standard deviation = 6.6 or 6.7 if we round.
In the solution the professor first subtracted the mean from the standard deviation and had an answer of 16.3, and then he set up a table and had the the z-score formula next to it. Let's say he calculated the Z-score for each grade, then how do I know how many people failed based on that?
I really don't understand whats going on in the problem, can someone PLEASE give me a detailed explanation on that? I'm desperate for help!!!
Explanation / Answer
if you just want to calculate number of fails then you don't need to calculate z value
simply failing threshold = 23-6.7 = 16.3
so less than it will fail i.e 15,14 will fail.
for calculating probability of failing students assuming normal
z = (x- mean)/sigma = 1(given)
and calculate cumulative prob. under 1
note: z= 1 also gives us
x = mean +sigma ; which i have used to calculate above.
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