Kirchhoff\'s Current Law Find all unknown currents and their directions in the c

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The current law = for every node, current going in = current goingout (a)From left to right current going in = 12+9+4= 25 I1 = 25A (from leftto right) for the second node (top right), current going in is 25(from left)+ 4 > 6 (going out) so current I2 must be leaving the node as well and 25+4= 6+I2 => I2 = 23A (top tobottom) for the third node (bottom right), 23A > 3, I3 = 23-3 = 20A (top to bottom) (b) similar to part (a) current going in the top left node = 20 > 9 that's leaving thenode, I1 = 20-9=11A (left to right) 11A going in to the middle node, 5A is leaving the node, soI2 = 11-5 = 6A (left to right) 6+8A = 14A is the current going in to the top right node,thereforeI3 = 14A (Top to bottom) for bottom right node, current going in is 14A > 4A going out,therefore I4 = 14-4 = 10A (leaving the node, thus top tobottom direction)

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