I was going over this problem: /introduction-to-electric-circuits-7th-problem-9-

Question

I was going over this problem: /introduction-to-electric-circuits-7th-problem-9-1005131.aspx
I have a doubt with the current division rules used incircuits 2 & 3 to the problem. Mainly, why does the 2nd(step 4)circuit use resistors 4 & 12 on the top and the3rd(step 6) only use resistor 12 on the top?
I have a doubt with the current division rules used incircuits 2 & 3 to the problem. Mainly, why does the 2nd(step 4)circuit use resistors 4 & 12 on the top and the3rd(step 6) only use resistor 12 on the top? I have a doubt with the current division rules used incircuits 2 & 3 to the problem. Mainly, why does the 2nd(step 4)circuit use resistors 4 & 12 on the top and the3rd(step 6) only use resistor 12 on the top?

Explanation / Answer

Ok first things first. You need to look at the diagram carefully!Lets look at the diagram in Step 4. The current I2 is going throught the 20k resistor. So uneed to find the current going through the other two resistors toknow how much current is going through that 20k resistor. So thatswhy the 4 & 12 are on the top. The second one has 12 on top since the I3 is goingthrough the resistors 4 and 12. So u need to find the current goingthrough the other resistor to solve for I3. Thats whythe 12 is on the top. All in all i made a little sentence that helps me remember thecurrent law that is. Current always hurts others. So if ur solvingfor I3 use the other resistors to find the current goingthrough it.

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.