A. Predict how bulbs 1 – 4 will rank according to brightness. Use the symbols >,
ID: 1831337 • Letter: A
Question
A. Predict how bulbs 1 – 4 will rank according to brightness. Use the symbols >, =, or <.
Each part below describes a single change made to the originalcircuit. After answering each part, return to the original circuit before going to the next part. B. How, if at all, will the brightness of bulb 1 change if oneinserts a new bulb along the path between point B and the negative terminal of the battery? Explain inwords. C. How, if at all, will the brightness of bulb 1 change if oneconnects a new bulb having its own path between points A and B? Explain in words. D. How, if at all, will the brightness of bulbs 1 and 3 changeif one unscrews bulb 4 from its socket (and leave the empty socket in the circuit)? Explain inwords. Each part below describes a single change made to the originalcircuit. After answering each part, return to the original circuit before going to the next part. B. How, if at all, will the brightness of bulb 1 change if oneinserts a new bulb along the path between point B and the negative terminal of the battery? Explain inwords. C. How, if at all, will the brightness of bulb 1 change if oneconnects a new bulb having its own path between points A and B? Explain in words. D. How, if at all, will the brightness of bulbs 1 and 3 changeif one unscrews bulb 4 from its socket (and leave the empty socket in the circuit)? Explain inwords.
Explanation / Answer
B) Bulb 1 will become dimmer because a new bulb between Node Band the negative source will be a bulb in series. Like Ipointed out, bulbs in series will be dimmer because the voltagemust sum up to the source.
C) Bulb 1 will not be affected because the new bulb would beparallel with the other bulbs between Nodes A and B. Thevoltage and current change in that parallel part will not affectbulb 1.
D) Ok, this one is a trick question. Mentioned earlier,3 and 4 are in series. What happens when you take one bulbout of a series circuit? The series circuit is shorted outand thus bulb three turns off. Now, if that part of theparallel is shorted out because of the missing bulb, then what doesthat make 1 and 2? Bulbs 1 and 2 are now in series becausethere is no part to make a parallel. So naturally you wouldassume that bulb 1 would be dimmer because bulbs in series aredimmer than that in parallel. This is incorrect. Bulb 1would not be afftected because the voltage across the bulb and thecurrent would not change. But what does this mean for bulb 2? Bulb two would become brighter to match that of bulb 1because now both bulbs are sharing the same voltages and have thesame current.
Hope that helped.
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.