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Suppose that we have a resistive circuit that has more current sources than volt

ID: 1833028 • Letter: S

Question

Suppose that we have a resistive circuit that has more current sources than voltage sources. The analysis method that we'd expect to work best is :

1. Brute force KCL and KVL
2. Thevenin's Theorem
3. Superposition Theorem
4. Mesh Analysis
5. Node Analysis

The resistance of a 1 kilometer long section of copper wire (s=5.7×10^7 S/m) whose radius is 1 mm is :

1. 5.6 Ohms
2. 0.56 Ohm
3. .056 Ohm
4. 56 Ohms

The AWG table describes

1. Standard wire sizes
2. Standard resistor sizes
3. Standard capacitor sizes
4. None of the given answers

Explanation / Answer

For a resistive circuit with more number of current sources than voltage sources, the best analysis methos is NODE ANALYSIS Given l = 1km = 1000m s = 5.7*107 S/m r = 1mm = 0.001m Area of cross section A = r2 = (3.14)(0.001)2 = 3.14*10-6 m2 Resistance R = l/A or R = l/sA R = 1000 / (5.7*107)(3.14*10-6) R = 5.6 AWG - American Wire Gauge describes STANDARD WIRE SIZES
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