According to Archimedes\' principal, the mass of a floating object equals the ma

Question

According to Archimedes' principal, the mass of a floating object equals the mass of the fluid displaced by the object. Use this principle to solve the following problems.

(a) A wooden cylinder 30.0 cm highs gloats vertically in a tube of water (density = 1.00 g/cm cube). The top of the cylinder is 14.1 cm above the surface of the liquid. What is the density of the wood?

(b) The same cylinder floats vertically in a liquid of unknown density. The top of the cylinder is 20.7 cm above the surface of the liquid. What is the density of the liquid?

Explanation / Answer

a) r230 x Dc= r2(30-14.1) x 1

hence Dc=0.53gm/cm3

b)  r230 x 0.53=r2(30-20.7) x Dl

hence Dl = 1.71gm/cm3

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