Find the value of RL that will be connected at terminals A-B that will absorb a

Question

Find the value of RL that will be connected at terminals A-B that will absorb a maximum power and specify the value of that power. Using Norton's theorem to find Vo shown in the figure below.

Explanation / Answer

A) to get Rl need theve equi>> then use the formula: Rl=Vth^2/4Rth(check ur text) theve equ: do the two mesh equations and subs for Vx, note IA=4amps loop1: -Vs(V drop across source) +Vx+(1)(4-Ib)=0 Vx=-j V or 1>subs in above and get Vs, then u have Vab=Vs+Vcoil (can get from +jIb)>>Vab=Vth now Rth: solve same but vs=0>> i.e. do KVL on nood Above 2Vx (connec it to resis) and get: but Vx is zero since capacitor end with A is open (no current)>> Rth=R1+j B) get Va=Vth by node voltage: (Vth)/1 + (Vth-2Vx)/1 + (Vth+8-4)/j=0 Vx= (Vth-2Vx)/1>>get Vth Now Zth>> short Volt. sources>>and get Vx> same: do the same node voltage: (Va)/1 + (Va-2Vx)/1 + (Va)/j=0 Vx= (Va-2Vx)/1>>get Va Now Capacitor is parall to R1 and series with coil>>do Zequiv. but Vx=0(no current)>>2Vx is short>> Zth=1ohm para to 1ohm=0.5 ohm PLZ RATE ASAP

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