this problem has been solved in my class. When solving you are suppose to do: oG

Question

this problem has been solved in my class. When solving you are suppose to do: oG/n= -(1)(8.314)(273+25) ln(1/2.51x10^4). Can someone explain to me why is there a one over the partial concentration in ln? thank you

4. (20 pts) The octanol-water partition coefficient of an environmental pollutant (the equilibrium concentration in liquid phase of octanol divided by the concentration in an aqueous phase) is 2.51 x 10" Calculate the free energy per mole to transport the pollutant from octanol to water. You may assume the pollutant is uncharged

Explanation / Answer

Here phase 2 is water while phase 1 is octanol. So we need to place the ration c_water/c_octanol as the argument of ln function. But the value given in the question is the concentration of octanol divided by concentration in water, i.e. C_octanol/C_water. Hence the one over the partial concentration comes in.

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