X-rays having various energies, Eo penetrated water that was 10 cm deep. Some X-

Question

X-rays having various energies, Eo penetrated water that was 10 cm deep. Some X-ray energy was absorbed by the water and some was transmitted. In Figure 1 the unshaded portion and the scale at the left give, for each Eg, the percent of Eo that was absorbed through each of Mechanisms A, B, C, and D (described in Table 1). In Figure 1 the shaded portion and the scale at the right give, for each Eo, the percent of Eo that was transmit- ted. The percent of Eo that was absorbed through a given mechanism or that was transmitted equals the height, in percent, of the respective sector (see the example for 0.2 MeV: 1 MeV= 1 million electron volts). 0 10 20 30 100 Mechanism C 90 80 70 Mechanism Mechanism B 50 50 Mechanism Example for E-0.2 MeV: 2% of E0 was absorbed through Mechanism A 70 80 90 100+ 30 -18% through Mechanism B, and -20 48% through Mechanism D. 32% of Eo was transmitted. 10 Eo (MeV) Figure 1 Figure adapted from Herbert L. Anderson, ed., Physics Vade Mecum, 1st ed. 01981 by The American Institute of Physics

Explanation / Answer

36)

Greatest to least absorbed. B and C seem to have the same values. So we should go wih [J] =D,B,A,C

37)Clearly it is 15 MeV. How?For 0.01 MeV percentage transmitted is zero. For 0.3 MeV it is about 38%. For 100 MeV that is about 78%. But it is about 84% for 15MeV

38) The true answer is about 45%. It is closest to 27%.

39) Percent absorbed + percent transmitted =100%

So answer is B

40) Clearly, only mechanism A should be the answer. Apparently there is no such option.

Related Questions

Navigate

• Browse (All)
• Browse X
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.