If someone can please indicate where is the correct location for the red X in pi

Question

If someone can please indicate where is the correct location for the red X in picture 2. The correct position of the Red X is incorrect. Let the intial direction of travel by the projectile bll be along x-axis. Since the target bail is intially at says that this is also the momentum after collision. Aher the colision both distances from the plumb line traveled by each bal the distances are proportional to the momenta. Whan the impact parameter P not equal to zero, the x-os Since the target bal s intially at the intial momentum is due to the projectle balil and s in the x direction. The principle of conservation of momentum um thr colision. Ater me colson b th bals go ito free fat and as the bais lard alte nial rorentum is ae the propese bel and n be x dmeton The s the bals land on carbon paper placed on top of a piece on peper, the balls leave dots on the proiectile and target bals have momentuninthe y die n Howevetthe vecty sum of momentum, un the, y dmton t paper marking the hornontal the horizontal velocities are unaffected by gravity Since the bals have the same mas . The horizontal distances ane directly reiated to the horizontal velocities of the balls since r t projectlile and target balis heve momentum in the y direction However, the vector sum of the momertum in the y direction s beñore colision: where the subscripts P and T refer to the projectie and target ball respectively. On the Fgure below, the location nere projectle bal lands at the posoon is labeled Pi adre co espodng posten tere target bal points PO On the Figure below, the location where projectile bal lands at the position is lsbeied Pl and the corresponding posticn for the target ball i sbeled . P2 and T2 represent subsequent tridls The inital momenturm i shown by ab id fiPaand finesse teabet tome seal enees-no plumb. T- Target Resullant mom rezne ovnaa.dree y beo. nepoet-reene. I The plumb line at

Explanation / Answer

We take the distance marked on the graph as the momenta

Initial mometumof the projectile before collision (P0) = 35 along +x-axis

Final momentum of the projectile after collision

                                                x-component = 27

                                                 y - component = 14

along y-axis inital momentum = 0

y-component of target after collison = -14

x-component of Target after collision = 35-27 = 8

The target ball will land at (8,-14) aftre collsion.

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