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Five equal charges Q = 2.17 muC each are equally spaced on a semicircle of radiu

ID: 1837370 • Letter: F

Question

Five equal charges Q = 2.17 muC each are equally spaced on a semicircle of radius R = 2.66 m as shown in the figure below: Find the magnitude of the force on a charge q = 1.48 p,C located at the center of the semicircle. 27.9 times 10^-3 N 3.2 times 10^-3 N 26 times 10^-3 N 4.1 times 10^-3 N 9.9 times 10^3 N 19.8 times 10^3 N 14 times 10^3 N 8.2 times 10^3N 14 times 10^3 N 6.3 x 10^-3 N Three non-conducting charged plates are shown in the figure above with their corresponding charge densities. The distance between each plate is d. If the plate at the bottom is grounded (i.e. set to 0 V), what is the voltage on the middle plate? -3sigma d/epsilon 2sigma d/epsilon -2sigma d/epsilon -sigma d/epsilon 3sigma d/epsilon sigma d/epsilon

Explanation / Answer

all charge are equidistant form q so magnitude of electricforce will be same
due to all Q.

|F| = k Q q / r^2

= (9 x 10^9 x 2.17 x 10^-6 x 1.48 x 10^-6) / (2.66^2)

|F| = 4.085 x 10^-3 N


azimuthal angle for Q'a are 90, 90+45,90+90, 90 + 135, 90 + 180 deg

= 90 , 135, 180, 225, 270 deg

Fx = 4.085 x 10^-3 ( cos90 + cos135 + cos180 + cos225 + cos270)

Fx = - 9.86 x 10^-3 N

Fy = 4.085 x 10^-3 ( sin90 + sin135 + sin180 + sin225 + sin270)

Fy = 0


Magniude = sqrt[Fx^2 + Fy^2] = 9.86 x 10^-3 N


Ans(e)