In a resistor configuration where there is 4 resistors of 8 ohms each, what woul

Question

In a resistor configuration where there is 4 resistors of 8 ohms each, what would be the resistance in ohms from A - B? The resistors are diagonal from each other, while a is on the left, b is on top, c is on the right, and d is on the bottom of the circle.
A) 6 B) 24 C) 16 D) 4.2 In a resistor configuration where there is 4 resistors of 8 ohms each, what would be the resistance in ohms from A - B? The resistors are diagonal from each other, while a is on the left, b is on top, c is on the right, and d is on the bottom of the circle.
A) 6 B) 24 C) 16 D) 4.2
A) 6 B) 24 C) 16 D) 4.2

Explanation / Answer

from your given details, we can see that

resistor a and b are in series

also resistor c and d are in series

and resistor ab and cd are in parallel

Now in series circuit

Rs = R1 + R2

in parallel circuit

1/Rp = 1/R1 + 1/R2

Now

Rab = Ra + Rb = 8 + 8 = 16 ohm

Rcd = Rc + Rd = 8 + 8 = 16 ohm

Now,

1/Req = 1/Rab + 1/Rcd

Req = Rab*Rcd/(Rab + Rcd)

Req = 16*16/(16 + 16) = 8 ohm

My answer is not in the options, I think there should have been a diagram given.

maybe I am misinterprating the language as "what do you mean by diagonal from each other in a circle"

So if you have a diagram please attach it.

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