1. What type of curve is the plot vertical position versus time? How does this r
ID: 1837723 • Letter: 1
Question
1. What type of curve is the plot vertical position versus time? How does this relate the formula for motion with constant acceleration?
2.Examine the plot of velocity versus time. Is the plot a straight line or a curved line? At what point in the ball’s motion does the velocity plot cross zero? What does this mean?
3. In the snapshot model at the left, count the vertical scale divisions (don’t worry about actual units of measure) From the point of release to the fifth snapshot. Then do the same at the tenth snapshot. Compare these two vertical displacements. What is their ratio? From the theoretical formulae, what would you expect their ratio to be?
4. Verify that the air density is set to 0 kg/m3. Unclick the “bounce” button. Run the simulation. Print or record the results. Then change the radius of the ball to 0.50 m. Run the simulation again. Compare the results of the second run with first run. Did the time to impact change? Why?
Explanation / Answer
The question paper contains multiple questions. Here is the answer to the first one.
Ans 1
The given position vs time curve shows the motion of an bouncing object (e.g ball).
The figure clearly shows the re-bound heights decrease progressively.
The object is undergoing free fall.
The path of fall is parabolic & it obeys the equation:
distance d = 1/2 g t2
g= acceleration due to gravity, t= time
This clearly relates to the equation of motion with constant acceleration:
d= ut +1/2 a t2
Here initial velocity u=0
acceleration a= acceleration due to gravity g.
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