help please 8. Red-green color blindness is an X-linked recessive trait in h uma
ID: 183815 • Letter: H
Question
help please
8. Red-green color blindness is an X-linked recessive trait in h umans. Polydactyly inant trait. Martha has 10 fingers and toes and standard color vision. Her mother is wildtype in all respects and her father is colorblind and has polydactyly. Bill is color blind and polydactylous. His mother had standard color vision and 10 fingers and toes. A. What are the genotypes of Bill and Martha? If Bill and Martha reproduce, what are the proportions of genotypes and phenotypes that may be found in their potential offspring? B.Explanation / Answer
A. Genotype of Martha will be DDXx
Since Martha has normal toes and fingers with normal vision her genotype will be DDXx where allele D represents dominant allele for polydactyly and X represents normal allele for color blindness and x represents mutant allele. Martha will be heterozygous for colorblind triat as she has received one mutant x chromosome from her father who is colorblind (daughter receives one X chromosome from father).
Genotype of Bill will be DdxY.
As he is colorblind and polydactylous.
B. If they marry ,genotypes and phenotypes in their offsprings would be
Parents : DDXx x DdxY
Gametes: DX, Dx Dx, DY, dx, dY.
Offsprings: DDXx, DdXx, DDXY, DdXY, DDxx, Ddxx, DDxY, DdxY
Phenotype:
DDXx = Normal vision and no polydactyly.
DdXx = Normal vision pokydactyly.
DDXY = NORMAL
DdXY = Normal vision polydactyly.
DDxx = colorblind and no polydactyly.
Ddxx= colorblind and polydactyly.
DDxY = colorblind and no polydactyly
DdxY = colorblind and polydactyly.
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