The answers are Part A) 167 lbs Part B) Nx= 100 lbs, Ny= 16.4 lbs I just want to

Question

The answers are Part A) 167 lbs Part B) Nx= 100 lbs, Ny= 16.4 lbs
I just want to know how to get these answers #32 A 50-lb stru of length L, attached to a wall with a frictionless pivot. A cable is attached 0.4L from the free end, and is attached to the wall, such that it makes an angle of 90° with the strut, and a 100 lbD block is attached at the free end, as showm. a) Find the tension in the cable, and b) the horizontal and vertical components of the 0.4 L/ 100 lbs 36.87° force of the pivot on the strut.

Explanation / Answer

(A) balancing moment about the hinge point;

Net torque = ( (L - 0.4L) T sin90) - (L/2 * 50 * sin(90-36.87)) - (L * 100 * sin(90-36.87)) = 0

0.6 T - 20 - 80 = 0

T = 166.67 lb ...........Ans

(B) in Horizontal,

Fx - Tsin36.87 = 0

Fx = 100 lb .......Ans ()

In vertical,

Fy + Tcos36.87 - 50 - 100 = 0

Fy = 16.67 lb . .....Ans

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