An airplane traveling at 300 m/s in a region where the earth\'s magnetic field i

Question

An airplane traveling at 300 m/s in a region where the earth's magnetic field is 2.8 times 10^-5 T. It travels vertical to the field. The potential difference induced between the tips of the airplane's wings is found to be 0.9V. What is the entire length of the airplane's wings A proton is observed in a magnetic field of strength 2.8 times 10^-5 T downward. What is the magnitude and direction of the force when the proton is moving at a speed of v = 1.8 times 10^5 m/s to the right? Give the radius of the orbit.

Explanation / Answer

Here ,

3)

magnetic field , B = 2.8 *10^-5 T

v = 300 m/s

let the length of the airplane wings is L

0.9 = 2.8 *10^-5 * 300 * L

L = 107.1 m

the length of airplane wings is 107.1 m

4)

magnetic field , B = 2.8 *10^-5 T

v = 1.8 *10^5 m/s

magnetic force = q * V X B

magnitude of force = 2.8 *10^-5 * 1.8 *10^5 * 1.602 *10^-19

magnitude of force = 8.074 *10^-19 C

direction of force = q * right X downwards

direction of force = upwards

the direction of magnetic force is upwards

let the radius is r

8.074 *10^-19 = 1.67 *10^-27 * (1.8 *10^5)^2/r

r = 67.1 m

the radius of orbit is 67.1 m

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