A cylindrical tank has a tight-fitting piston that allows the volume of the tank

Question

A cylindrical tank has a tight-fitting piston that allows the volume of the tank to the changed. The tank originally contains 0.310 m^3 of air at a pressure of 4.30 atm. The piston is slowly pulled out until the volume of the gas is increased to 0.390 m^3. If the temperature remains constant, what is the final value of the pressure? V = .310 m^3 P_1 V_1 = P_2 V_2 P = 4.30 atm P_1 V_1 = P_2 V_2 4.3 (.310) = .390 m^3 (P_2) P_2 = 3.42 atm How many water molecules are there in a 2.00 L bottle of water? 2L|1000|_8.015| 6.02 times 10^23 [6.68 times 10^25 molecules H_2O]

Explanation / Answer

Both ans are right,

For second....

18 gm of water contain number of molecules = 6.02*10^23

So in 2 liter = 2 liter*6.02×10^23/18gm

= (2000gm* 6.02*10^23)/18gm

= 6.689*10^25 molecule

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.