can you show the step by step to the answer Coulomb\'s law for the magnitude of

Question

can you show the step by step to the answer

Coulomb's law for the magnitude of the force F between two particles with charges Q and Q' separated by a distance d is |F| = K |QQ'|/d^2 Where K = What is the net force/4 pi pi epsilon_0, and epsilon_0 = 8.854 Times 10^-12 C^2/(N middot m^2) is the permittivity of free space. Consider two point charges located on the x axis: one charge, q_1 = -14.0 nC, is located at x_1 = -1.700 m; the second charge, q_2 = 40.0 nC, is at the origin (x = 0.0000) What is the net force exerted by these two charges on a third charge q_3 = 45.0 nC placed between q_1 and q_2 at x_3 = -1.160 m? Your answer may be positive or negative, depending on the direction of the force. Express your answer numerically in newtons to three significant figures.

Explanation / Answer

force due to q1 on q3 = Kq1q3/a^2 = 9*10^9*14*10^-9*45*10^-9 / (0.54^2)

= 1.94*10^-5 N (to the right)

Force due to q2 on q3 = Kq1q2/b^2 = 9*10^9*40*10^-9*45*10^-9 / (1.16^2)

= 1.2*10^-5 N (to the right)

Net force on charge q3 = 1.94*10^-5 + 1.2*10^-5

= 3.14*10^-5 N (to the right)

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