A plastic rod has a charge of-2.0 C. How many electrons must be removed so that

Question

A plastic rod has a charge of-2.0 C. How many electrons must be removed so that the charge on the rod becomes +3.o mu C? Three identical metal spheres, A, B, and C initially have net charges as shown. Spheres A and B are now touched together and then separated. Sphere C is then touched to sphere A and separated from it. Lastly, sphere C is touched to sphere B and then separated from it (a) How much charge ends up on sphere C? What is the total charge on the three spheres (b) before they are allowed to touch each other and (c) after they have touched?

Explanation / Answer

1) total charge removed = - 2uC - (3uC) = - 5uC

and q = n e

-5 x 10^-6 C = n ( -1.6 x 10^-19 C)

n = 3.125 x 10^13

2) When A and B are touched.

so total charge on system = 5q + (-1q) = 4q

when they are sepaarated, they will carry charge in equal magnitude.

qA = qB = + 2q

now C is touched to A.

total charge = 2q + 0 = 2q

after separation charge on both.

qA = qC = + 1q

now C and B are touched,

total charge = +1q + 2q = + 3q

after separation,

qC = qB = +1.5q

(A) qC = + 1.5q

(B) before they were allowed to touch.

total charge = +5q + (-1q) + 0 = 4q

(C) after :

= 1q + 1.5q + 1.5q =+ 4q

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